Spaced Out?

Carvia Tech | September 10, 2019 | 1 min read | 2 views | Python Coding Problems


Given 3 different integer numbers, determine if the difference between the smallest number and the middle number is the same as the difference between the middle number and the largest number.

The numbers can be entered in any order. If the differences are exactly the same the program should indicate the numbers are "Spaced Out" otherwise the numbers are "NOT Spaced Out".

def spaced_out(list_of_num):
    if len(list_of_num) > 3:
        list_of_num = list_of_num[:3]
        print("keeping only first three elements") (1)
    if abs(list_of_num[0]-list_of_num[1]) == abs(list_of_num[1]-list_of_num[2]): (2)
        return "Spaced Out"
    else:
        return "NOT Spaced Out"
1 In case, input is more than three numbers then we will be considering only first three numbers as given in problem statement.
2 We are checking if the array is spaced out or not by using abs function in python
Input
print(spaced_out([1,3,5,7]))
Output
keeping only first three elements
Spaced Out

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